## SAT Question of the Day December 29th 2012 ### The same can be done with the other point (-2, 0).

50% out of >140,000 answers – a moderate level of difficulty. If you had problems with understanding the solution – you should review function, quadratics, graphs, and solving equations with one variable.

## SAT Question of the Day December 26th 2012 ## SAT Question of the Day December 20th 2012 In the xy-plane, the graph of the equation above assumes its maximum value at . What is the value of b?

## SAT question of the Day Dec 8th 2012

### We would obtain: 2X-Y-Z=0 which is the correct answer.

55% got it right out of 140,000 responses. A intermediate level question. You will probably get it right just be attentive of the time you spend answering it.

Hanan

## SAT question of the Day Dec 5th 2012

### In the triangles above, ### Now we can solve the equation. 3 times (60-45) is 3 times 15 or 45 degrees.

This was a relative easy question with 72% correct answers out of ~160,000 responses.

Hanan

## SAT Question of the Day Dec 2nd 2012

The stopping distance of a car is the number of feet that the car travels after the driver starts applying the brakes. The stopping distance of a certain car is directly proportional to the square of the speed of the car, in miles per hour, at the time the brakes are first applied. If the car’s stopping distance for an initial speed of miles per hour is feet, what is its stopping distance for an initial speed of miles per hour?

### What else do we know about the link between the two variables (stopping distance as function of speed)?  We know it is linked through an increase that is proportional to the “square of the speed of the car“. This is a parabola that passes through (0,0). If the stopping distance when traveling at 20 mils per hour is 17 feet and the stopping distance is directly proportional to the square of the speed of the car, when you increase the speed by a certain factor – the stopping distance will increase by the same factor squared. That implies that if we double the speed to 40 miles per hour the stopping distance will increase by 2 square or by a factor of 4 to 68 feet. Note that directly proportional does not always mean a linear relation.

The success rate answering this question was 38% out of ~200,000 submissions – you can see that reading is a critical part of math. I assume most of the wrong answers were 34 feet as this is “directly proportional” but linear and not quadratic.